Stephen Drew Not In Lineup For Red Sox Vs. Orioles
BOSTON (CBS) — The Boston Red Sox agreed to pay Stephen Drew $10 million to come and play for them this season, which is a fairly typical agreement between a team and a player.
What’s strange is that the Sox haven’t been asking Drew to play all that much.
The shortstop is once again not in the Red Sox starting lineup on Monday night, as the Sox visit the Orioles for the first in a three-game set.
Drew started in Sunday night’s game, going 0-for-3 at the plate before Jonathan Herrera pinch hit for him in the top of the eighth inning.
In total, Drew played in just four of the Sox’ six games last week, and Monday’s absence will mean he’s sat for three out of seven games since joining the team.
What makes Monday’s absence hard to understand is that the Sox are facing a righty in Bud Norris. Drew owns a .462 batting average, .588 on-base percentage and 1.357 OPS in 17 career plate appearances against Norris.
Since rejoining the Red Sox last Monday, Drew is hitting .071 (1-for-14) with two walks. He’s successfully made 16 assists and six putouts at shortstop without making an error.
UPDATE: Manager John Farrell revealed that Drew is suffering from oblique tightness, and the team is keeping him out of the lineup as a precaution.
The complete Red Sox lineup for Monday vs. Baltimore is below:
1. Brock Holt, LF
2. Xander Bogaerts, 3B
3. Dustin Pedroia, 2B
4. David Ortiz, DH
5. Mike Napoli, 1B
6. Daniel Nava, RF
7. Grady Sizemore, CF
8. Jonathan Herrera, SS
9. David Ross, C
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